Cr (OH) 3 + H2SeO4. Write the reactions of formation of all possible salts.

If chromium (III) hydroxide interacts with sulfuric acid, then chromium (III) sulfate and water (exchange) will form, that is, the formation of a medium salt.

Let’s write down the reaction of interaction of chromium (III) hydroxide and sulfuric acid:

2Cr (OH) 3 + 3H2SO4 → Cr2 (SO4) 3 + 6H2O

Let us write down the ionic equations, taking into account that

Knowing that chromium (III) hydroxide and water do not dissociate into ions, that is, do not decompose, then we write down the ionic equations:

2Cr (OH) 3 + 6Н + + 3SO4 2- → 2Cr 2+ + 3SO4 2- + 6H2O

2Cr (OH) 3 + 6H + → 2Cr 2+ + 6H2O

The first equation is called complete ionic, and the second is called reduced ionic.