Crystalline iodine weighing 0.0254 g during titration reacted with 8.5 ml of Na2S2O3 solution. Determine the molar concentration
| December 3, 2020 | education
2Na2S2O3 + I2 = Na2S4O6 + 2NaI
n (I2) = m \ M = 0.0254 \ 254 = 0.0001 mol
n (Na2S2O3) = 0.0001 * 2 = 0.0002 mol
c = n \ V = 0.0002 \ 0.0085 = 0.024 mol \ L (M)
Answer: c = 0.024 mol \ L (M)
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