Cut a square with a side of 10 cm, cut off the corners by 2 cm. Find the area of the remaining figure.

The cut corners of the square have rectangular, isosceles triangles with a leg length of 2 cm.

Determine the area of the triangle AKM.

Skm = AK * AM / 2 = 2 * 2/2 = 2 cm2.

The area of the square is equal to: Savsd = AB ^ 2 = 10 ^ 2 = 100 cm2.

Then the area of the remaining figure is equal to: S = Savsd – 4 * Sacm = 100 – 4 * 2 = 92 cm2.

Answer: The area of the remaining figure is 92 cm2.



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