Cycle pedist moving evenly drives 40m in 4 seconds. What path will he travel when driving at the same speed in 15 seconds?
| May 31, 2021 | education
These tasks: the cyclist moved evenly (V = const); t1 (first time of movement) = 4 s; S1 (first distance traveled) = 40 m; t2 (second movement time) = 15 s.
We express the path that a cyclist will cover in 15 seconds from the equality: S1 / t1 = S2 / t2 = V, whence S2 = S1 * t2 / t1.
Calculation: S2 = 40 * 15/4 = 150 m.
Answer: When moving at a constant speed, the cyclist will travel 150 meters in 15 seconds.
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