Cyclopropane weighing 36 g under normal conditions occupies a volume (l) equal to …

Given:
m (C3H6) = 36 g
Vm = 22.4 l / mol

To find:
V (C3H6) -?

Decision:
1) Using the periodic system of D.I.Mendeleev, calculate the molar mass of cyclopropane:
M (C3H6) = Mr (C3H6) = Ar (C) * N (C) + Ar (H) * N (H) = 12 * 3 + 1 * 6 = 42 g / mol;
2) Calculate the amount of cyclopropane substance:
n (C3H6) = m (C3H6) / M (C3H6) = 36/42 = 0.86 mol;
3) Calculate the volume of cyclopropane (under normal conditions):
V (C3H6) = n (C3H6) * Vm = 0.86 * 22.4 = 19.3 liters.

Answer: The volume of C3H6 is 19.3 liters.