Data through the communication channel was transmitted within 10 minutes. Determine the maximum

Data through the communication channel was transmitted within 10 minutes. Determine the maximum amount of data if their transfer rate was 32 Kbps?

Let’s translate 10 minutes. in sec.

10 min. * 60 sec. = 600 sec.

32 Kbps * 600 sec. = 19 200 kbps.

Let’s translate into bits:

19 200 Kb * 1024 = 19 660 800 bit.

We translate into bytes.

Considering that 1 byte = 8 bits.

19,660,800: 8 = 2,457,600 bytes.

We translate into kilobytes:

2,457,600: 1,024 = 2,400 KB.

We translate into megabytes:

2,400: 1,024 = 2.3 MB.

Answer: The maximum amount of data was 2.3 MB.