Data transfer over ADSL connection took 2 minutes. During this time, a file was transferred, the size of which was 3,750 KB. Determine the minimum rate (bps) at which this transmission is possible.
2 minutes = 120 seconds. If during this time a file of 3750 Kbytes was transferred, therefore, 3750: 120 = 31.25 Kbytes were transferred in 1 second.
Therefore, the minimum data transfer rate is 31.25 KB / sec = 31.25 * 1024 = 32000 bytes / sec = 256000 bit / sec.
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