DBE is an isosceles triangle. BK is the height of the triangle, BK = 4 cm. The base DE of the triangle is 2 cm

DBE is an isosceles triangle. BK is the height of the triangle, BK = 4 cm. The base DE of the triangle is 2 cm longer than BK. The lateral side of the triangle is 1 cm longer than BK. find the perimeter of the triangle.

The perimeter of a triangle is equal to the sum of the lengths of the sides and the base.

We find the length of the base:
DE = ВK + 2 cm = 4 cm + 2 cm = 6 cm.

We find the length of the side:
DB = ВK + 1 cm = 4 cm + 1 cm = 5 cm.

Determine the perimeter of triangle DBE:
P (DBE) = DE + 2DB = 6 + 2 × 5 = 16 cm.

Answer: The perimeter of triangle DBE is 16 cm.



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