Derive the formula for alkyne containing 88.24% carbohydrate 11.11%
Given:
w% (C) = 88.24%
w% (H) = 11.76%
To find:
Formula -?
Decision:
1) Find the molecular weight of alkyne by the formula:
w% (element) = Ar (element): Mr (alkyne) * 100%
Mr (alkyne) = Ar (element): w% (element) * 100%
We substitute carbon data into the formula:
Mr (alkyne) = 12: 88.24% * 100% = ~ 13.
2) Knowing the mass fraction of carbon, we find its molecular weight in the composition and the number of atoms:
13 – 100%
x – 88.24%,
then x = 88.24% * 13: 100% = 12.
N (C) = 12: Mr (C) = 12: 12 = 1 atom
3) Then the molecular weight of hydrogen accounts for 13 – 12 = 1 atom.
N (H) = 1: Mr (H) = 1 atom.
We got a substance with the formula CH. Such a substance does not exist in nature, therefore we multiply the indices of the elements by 2. We get C2H2 – acetylene.
Answer: C2H2 – acetylene.