Derive the formula for alkyne containing 88.24% carbohydrate 11.11%

Given:

w% (C) = 88.24%

w% (H) = 11.76%

To find:

Formula -?

Decision:

1) Find the molecular weight of alkyne by the formula:

w% (element) = Ar (element): Mr (alkyne) * 100%

Mr (alkyne) = Ar (element): w% (element) * 100%

We substitute carbon data into the formula:

Mr (alkyne) = 12: 88.24% * 100% = ~ 13.

2) Knowing the mass fraction of carbon, we find its molecular weight in the composition and the number of atoms:

13 – 100%

x – 88.24%,

then x = 88.24% * 13: 100% = 12.

N (C) = 12: Mr (C) = 12: 12 = 1 atom

3) Then the molecular weight of hydrogen accounts for 13 – 12 = 1 atom.

N (H) = 1: Mr (H) = 1 atom.

We got a substance with the formula CH. Such a substance does not exist in nature, therefore we multiply the indices of the elements by 2. We get C2H2 – acetylene.

Answer: C2H2 – acetylene.



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