Derive the formula for an acidic substance containing 37.5% carbon 12.5% hydrogen and 50% oxygen

Derive the formula for an acidic substance containing 37.5% carbon 12.5% hydrogen and 50% oxygen, the relative density of the svv of this substance by odor is 16

Let’s designate the unknown substance as CxHyOz.
Let’s compose the ratio of the percentage to molar mass.
CxHyOz = 37.5 / 12: 12.5 / 1: 50/16 = 3.125: 12.5: 3.125.
Let’s round to the nearest whole number by dividing by the smallest value.
CxHyOz = 1: 4: 1.
The molar mass of the resulting substance is Mr (CH4O) = 32.
Let us find the true molar mass of a substance, knowing the vapor density of hydrogen.
Mr (CxHyOz) = D (H2) • Mr (H2) = 16 • 2 = 32.
This means that the formula of the substance is set correctly CH4O or CH3OH – methanol.