Derive the formula for an organic substance obtained in a mass of 120 g by reacting a bromoalkane with 80 g of an aqueous

Derive the formula for an organic substance obtained in a mass of 120 g by reacting a bromoalkane with 80 g of an aqueous solution of sodium hydroxide. In the answer, indicate the name of the resulting substance. 1) octanol 2) propene 3) propanol

Let’s write the reaction equation: СnH2n + 1O + NaOH—> CnH2n + 2O + NaBr Find n NaOH n = m / M n (NaOH) = 80g / 40g / mol = 2 mol Find M CnH2n + 2O M = m / n M = 120g / 2 mol = 60 g / mol 14n + 2 + 16 = 60 14n = 42 n = 3
Answer: C3H7OH – propanol