Derive the formula of a substance containing 2.2% hydrogen iodine 55.7% oxygen 42.1%

Derive the formula of a substance containing 2.2% hydrogen iodine 55.7% oxygen 42.1%
Let the percentage given by the condition be taken as the mass of the substances listed above
Find the molar masses according to the periodic table
M (H) = 1 (g / mol)
M (I) = 127 (g / mol)
M (O) = 16 (g / mol)
Let’s calculate the ratios of the amounts of substances by the formula: n = m / M
2.2 / 1: 55.7 / 127: 42.1 / 16
Let’s count
2.2: 0.439: 2.63
Divide by the smallest value and get
5: 1: 6
We have the formula H5IO6
This is the answer. It is orthoiodic acid