Derive the molecular formula of a hydrocarbon containing 84% carbon if 500 ml of its vapor at normal

Derive the molecular formula of a hydrocarbon containing 84% carbon if 500 ml of its vapor at normal conditions. have a mass of 2.232.

N = m / M
n = V / V (molar)
m / M = V / V (molar)
We derive the molar mass:
M = V (molar) * m / V
M = 22.4 (g / mol) * 2.232g / 0.5l = 100 g / mol
if it is a hydrocarbon, then it contains C and H, therefore:
w (C) = M (C) / M (connections)
M (C) = w * M (compounds) = 0.84 * 100g / mol = 84 g / mol
since M (C) = 12 g / mol
then in our compound there are 84/12 C atoms, that is, 7 atoms.
hydrogen – 16%
16 hydrogen atoms come out
Answer: С7H16 – heptane, alkane.