Derive the molecular formula of a substance consisting of carbon, hydrogen, iodine, the mass fraction of which

Derive the molecular formula of a substance consisting of carbon, hydrogen, iodine, the mass fraction of which is 8.45%, 2.11% and 89.44%, respectively, the vapor density of the substance for oxygen corresponds to 4.4375.

Given:
w (C) = 8.45% = 0.0845
w (H) = 2.11% = 0.0211
w (I) = 89.44% = 0.8944
D (O2) = 4.4375
Formula -?
Decision:
D (O2) = M (CnHyIz) / Mr (O2)
M (CnHyIz) = D (O2) * Mr (O2)
M (CnHyIz) = 4.4375 * 16 * 2 = 142
M (C) = w (C) * M (CnHyIz)
M (C) = 0.0845 * 142 = 12
In the same way as carbon, we find hydrogen and iodine
M (H) = 142 * 0.0211 = 3
M (I) = 0.8944 * 142 = 127
n (C) = 12/12 = 1
y (H) = 3/1 = 3
z (I) = 127/127 = 1
CH3I – iodomethane