Derive the molecular formula of the hydrocarbon, if the mass fraction of carbon in this substance
Derive the molecular formula of the hydrocarbon, if the mass fraction of carbon in this substance is 82.75℅, the molar mass is 58 g / mol
1. Let us take the mass of hydrocarbon per 100 g.
2. Let’s find the mass of carbon in the substance.
100 g – 100%,
m (C) – 82.75%
m = (100 g × 82.75%): 100% = 82.75 g.
3. Let’s find the mass of hydrogen.
100 g – 82.75 = 17.25 g
4. Let’s find the amount of matter of atoms in the compound.
n = m: M.
n (H) = 17.25: 1 = 17.25 mol.
n (C) = 82.75: 12 = 6.9 mol.
5. Find the ratio of the amounts of substances.
n (C): n (H) = 6.9: 17.25.
We get: n (C): n (H): n (O) = 1: 2.5.
6. Taking into account that the molar mass of a substance is 58 g / mol, we establish the formula of the substance.
Formula C4H10 – butane.
Answer: С4H10 – butane.