Derive the simplest formula for phosphorus sulfide, knowing that it contains 60.8% sulfur?

| September 6, 2021 | education

Given:

w% (S) = 60.8%

Find:

Formula -?

Solution:

1) Find the molecular weight of the compound by the formula:

w% (element) = Ar (element): Mr (substance) * 100%

Mr (substance) = Ar (element): w% (element) * 100%

We substitute the sulfur data:

Mr (substances) = 32: 60.8% * 100% = 53

2) Knowing the mass fraction of sulfur, we find its molecular weight in the composition and the number of atoms:

53 – 100%

x – 60.8%,

then x = 32 (1 action each).

N (S) = 32: Mr (S) = 1 atom.

3) Then the molecular weight of phosphorus accounts for 53 – 32 = 21

N (P) = 21: Mr (P) = 21: 31 = 2/3 atoms

We have obtained a substance with the simplest formula P2 / 3S. There is no such substance in nature, so we multiply the indices by 3. We get P2S3 – phosphorus sulfide 3.

Answer: P2S3 – phosphorus sulfide 3.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.