Determine how high the squid will jump vertically upward if its initial speed is 40 km / h.

Problem data: V0 (initial speed of the squid) = 40 km / h (in SI system V0 = 11.11 m / s).

Constants: g (acceleration of gravity, acceleration of squid) ≈ 10 m / s2.

The height to which the squid can jump is determined by the formula (slow motion): S = H = (V0 ^ 2 – V ^ 2) / 2a = (V0 ^ 2 – 0 ^ 2) / 2g.

Let’s calculate: H = (11.11 ^ 2 – 0 ^ 2) / (2 * 10) = 6.17 m.

Check: En = Ek and m * g * h = m * V0 ^ 2/2, whence h = V0 ^ 2 / 2g = 6.17 m.

Answer: The squid can jump to a height of 6.17 m.



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