Determine how many grams of potassium oxide is formed by the interaction of 100 g of potassium and 50 liters of oxygen.

1. We write down the reaction equation:

4K + O2 = 2K2O;

2.find the chemical amount of potassium and use it to calculate the amount of oxide:

n (K) = m (K): M (K) = 100: 39 = 2.564 mol;

n (K2O) = n (K): 2 = 2.564: 2 = 1.282 mol;

3. find the amount of oxygen and calculate the amount of potassium oxide from it:

n (O2) = V (O2): Vm = 50: 22.4 = 2.232 mol;

n (K2O) = n (O2) * 2 = 2.232 * 2 = 4.464 mol, the chemical amount found through potassium is less, therefore, further calculation is carried out on the basis of deficiency;

4. find the mass of the oxide:

m (K2O) = n (K2O) * M (K2O);

M (K2O) = 39 * 2 + 16 = 94 g / mol;

m (K2O) = 1.282 * 94 = 120.51 g.

Answer: 120.51 g.