Determine how many moles of zinc burned out if 11.2 L of oxygen reacted?
June 2, 2021 | education
| Zinc is oxidized by oxygen. The reaction is described by the following equation.
Zn + ½ O2 = ZnO;
1 mol of metallic zinc reacts with 0.5 mol of oxygen. This synthesizes 1 mole of zinc oxide.
Let us determine the chemical amount of oxygen contained in 11.2 liters.
To do this, we divide the volume of gas by the volume of 1 mole of gas, which is 22.4 liters.
N O2 = 11.2 / 22.4 = 0.5 mol;
With this amount of oxygen, 0.5 x 2 = 1 mole of zinc will react.
Let’s calculate its mass.
To do this, multiply the amount of the substance by the weight of 1 mole of the substance.
M Zn = 65 grams / mol;
m Zn = 1 x 65 = 65 grams;
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