Determine how many times the module of the linear speed of the end of the minute hand of the clock tower

| April 26, 2021 | education

Determine how many times the module of the linear speed of the end of the minute hand of the clock tower is greater than the module of the linear speed of the end of the hour hand if the length of the minute hand is 170 cm, and the length of the hour hand is 130 cm.

To find out the ratio of the moduli of the linear velocities of the ends of the minute and hour hands, consider the formula: k = Vms / Vchs = (2 * Π * Rms / Tms) / (2 * Π * Rchs / Tchs) = Tchs * Lms / (Lchs * Tms) …

Const: Tchs – hour hand period (Tchs = 43200 s); Tms – period of the minute hand (Tchs = 3600 s).

Data: Lms – length of the minute hand (Lms = 170 cm); Lhs – the length of the hour hand (Lhs = 130 cm).

Let’s perform the calculation: k = Tchs * Lms / (Lchs * Tms) = 43200 * 170 / (130 * 3600) = 15.6923 ≈ 15.7.

Answer: The ratio of the linear velocity modules, according to the calculation, is 15.7.



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