# Determine how much coke is required to heat 1.5 tons of scrap iron from 20

Determine how much coke is required to heat 1.5 tons of scrap iron from 20 degrees to the melting point and melt. The efficiency of the melting furnace is 60%.

To find out the required mass of coke, heating and melting of the taken iron scrap, we use the formula: ηп = mzhl * (CFe * (tmelt – t0) + λFe) / (qk * mk), from where we express: mk = mzhl * (CFe * (tmelt – t0) + λFe) / (qк * ηп).

Const: СFe – beats. heat capacity of iron (СFe = 452 J / (kg * K)); tmelt – temperature of the beginning of melting (tmelt = 1538.85 ºС); λFe – beats heat of fusion of iron (λFe = 27 * 10 ^ 4 J / kg); qk – beats. heat of combustion of blast furnace coke (qc = 30.4 * 10 ^ 6 J / kg).

Data: mzhl is the mass of iron scrap (mzhl = 1.5 t; in the SI system mzhl = 1.5 * 10 ^ 6 kg); t0 – early. scrap temperature (t0 = 20 ºС); ηп – efficiency of the used melting furnace (ηп = 60% = 0.6).

Let’s perform the calculation: mk = mzhl * (CFe * (tmelt – t0) + λFe) / (qk * ηp) = 1.5 * 10 ^ 3 * (452 ​​* (1538.85 – 20) + 27 * 10 ^ 4) / (30.4 * 10 ^ 6 * 0.6) ≈ 78.7 kg.

Answer: You will need to spend 78.7 kg of blast furnace coke.

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