Determine how much gas is released when 2.4 g of magnesium react with sulfuric acid.

univerkov | January 17, 2021 | education

Given:
m (Mg) = 2.4 g
To find:
V (H2)
Decision:
Mg + H2SO4 = MgSO4 + H2
n (Mg) = m / M = 2.4 g / 24 g / mol = 0.1 mol
n (Mg): n (H2) = 1: 1
n (H2) = 0.1 mol
V (H2) = n * Vm = 0.1 mol * 22.4 L / mol = 2.24 L
Answer: 2.24 l

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