Determine how much heat an aluminum pan weighing 290 g and 1.4 liters of water in it received when heated from 23 ° C

Determine how much heat an aluminum pan weighing 290 g and 1.4 liters of water in it received when heated from 23 ° C to boiling at 100 ° C. The specific heat capacity of aluminum is 920 J / (kg · ° C), the specific heat capacity of water is 4200 J / (kg · ° C), and the density of water is 1000 kg / m³.

Given: m1 (saucepan) = 290g, V2 = 1.4L, t1 = t3 = 23C, t2 = t4 = 100C, c1 = 920 J / kg * C, c2 = 4200 J / kg * C, p2 = 1000 kg / m ^ 3
SI: m1 = 0.29kg, V2 = 0.0014m ^ 3
Find: Q
Decision:
Q = Q1 + Q2
Q1 = c1m1 (t2 – t1)
Q2 = c2m2 (t4 – t3)
m2 = p2V2
m2 = 1000 kg / m ^ 3 * 0.0014 m ^ 3 = 1.4kg
Q2 = 4200 J / kg * C * 1.4kg * (100C – 23C) = 452760Q
Q1 = 920 J / kg * C * 0.29kg * (100C – 23C) = 20543Q
Q = 20543 J + 452760 J = 473303 J
Answer: Q = 473303 J