Determine how much heat is needed to turn 2 kg of water at 50 C into steam.

Initial data: m (mass of water) = 2 kg; t0 (initial temperature) = 50 ºС.
Reference values: t (temperature at which vaporization starts) = 100 ºС; C (specific heat) = 4200 J / (kg * K); L (specific heat of vaporization) = 2.3 * 10 ^ 6 J / kg.
The amount of heat that is needed for vaporization: Q = C * m * (t – t0) + L * m = (C * (t – t0) + L) * m.
Let us perform the calculation: Q = (4200 * (100 – 50) + 2.3 * 10 ^ 6) * 2 = 5020000 J = 5.02 MJ.
Answer: 5.02 MJ of heat is required.



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