Determine how much hydrogen will be released if a solution of hydrochloric

Determine how much hydrogen will be released if a solution of hydrochloric acid weighing 200 g with a mass fraction of 0.164 is added to aluminum weighing 8.5 g?

The reaction of interaction of aluminum with hydrochloric acid is described by the following chemical equation:

Al + 3HCl = AlCl3 + 3/2 H2;

When 1 molecule of metal is dissolved, 1 molecule of aluminum chloride is formed. This requires 3 molecules of hydrochloric acid and 1.5 hydrogen molecules are released, containing 6 atoms of this element.

Let’s calculate the chemical amount of a substance in 200 grams of 16.4% acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 200 x 0.164 / 36.5 = 0.899 mol;

M Al = 27 grams / mol;

N Al = 8.5 / 27 = 0.315 mol;

With 0.899 mol of acid, 0.2997 mol of metal will react. The same amount of hydrogen will be released.

Let’s calculate its volume.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

The volume of hydrogen will be:

V H2 = 0.2997 x 22.40 = 6.71 liters;