Determine how much iron oxide 3 can dissolve in 14.6 grams of hydrochloric acid.

Let’s implement the solution:
1. Let’s write the reaction equation:
Fe2O3 + 6HCl = 2FeCl3 + 3H2O – ion exchange reaction, ferric chloride was obtained;
2. Let’s define the molar masses of the reacting substances:
M (Fe2O3) = 55.8 * 2 + 16 * 3 = 159.6 g / mol;
M (HCl) = 1 + 35.5 = 36.5 g / mol;
3. Let’s calculate the amount of HCl mol according to the formula:
Y (HCl) = m / M = 14.6 / 36.5 = 0.4 mol;
4. Let’s make the proportion:
X mol (Fe2O3) – 0.4 mol (HCl);
-1 mol                – 6 mol hence, x mol (Fe2O3) = 1 * 0.4 / 6 = 0.06 mol;
5. Determine the mass of iron oxide (3):
M (Fe2O3) = Y * M = 0.06 * 159.6 = 9.58 g.
Answer: to carry out the reaction, iron oxide weighing 9.58 g is required.