Determine how much sulfuric acid is needed to completely dissolve 2 mol of zinc.

Determine how much sulfuric acid is needed to completely dissolve 2 mol of zinc. How much of the salt substance is formed in this case?

Let’s write down the reaction of dissolving zinc with acid:

H2SO4 + Zn = ZnSO4 + H2O;

1. Let’s find the chemical amount of sulfuric acid:

n (H2SO4) = n (Zn) = 2 mol;

2. find the mass of the acid:

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

m (H2SO4) = 2 * 98 = 196 g;

3. Determine the amount of zinc sulfate formed:

n (ZnSO4) = n (H2SO4) = 2 mol.

Answer: 196 g H2SO4, 2 mol ZnSO4.