Determine how much the air pressure in the vessel is higher than atmospheric if the difference

Determine how much the air pressure in the vessel is higher than atmospheric if the difference in water level in the liquid manometer is 5 cm.

Initial data: Δh (difference in water levels in a liquid manometer) = 5 cm (0.05 m).

Constants: ρ (density of water in a liquid manometer) = 1000 kg / m3; g (acceleration due to gravity) = 9.81 m / s2.

The difference between the pressures of atmospheric air and air in the vessel will be equal to the change in the hydrostatic pressure in the liquid manometer: ΔP = ρ * g * Δh.

Let’s calculate: ΔP = 1000 * 9.81 * 0.05 = 490.5 Pa.

Answer: The air pressure in the vessel is 490.5 Pa higher than atmospheric pressure.