Determine if there is a triangle with a perimeter of 47 cm in which one side is 10 cm less
Determine if there is a triangle with a perimeter of 47 cm in which one side is 10 cm less than the other and 5 cm more than the third.
1. Let’s denote one side of the triangle by x cm.
Then, according to the condition of the problem, its second side will be equal to (x – 10) cm, and the third (x + 5) cm.
2. Let’s write down and solve the equation, since we know that the sum of all three sides is 47 cm.
x cm + (x – 10) cm + 9x + 5) cm = 47 cm;
3 x = 47 cm + 10 cm – 5 cm;
3 x = 52 cm, whence x = 52: 3 = 17 1/3 cm.
Determine the length of the second side
x – 10 cm = 17 1/3 cm – 10 cm = 7 1/3 cm.
The value of the third party is calculated as the addition action
x + 5 = 17 1/3 cm + 5 cm = 22 1/3 cm
Let’s check: 17 1/3 + 7 1/3 + 22 1/3 = 47 cm.
Answer: Such a triangle exists.