Determine in which compound the mass fraction of hydrogen is greater: a) pentane C5H12 and benzene
Determine in which compound the mass fraction of hydrogen is greater: a) pentane C5H12 and benzene C6H6 b) ammonia NH3 and hydrogen peroxide H2O2 c) methane CH4 and hydrazine N2H4 d) ethylene C2H4 and silane SiH4
w = (M (element) / M (substance)) * 100.
a) C5H12 w (H) = (M (H) / M (C5H12)) * 100;
M (C5H12) = 5 * 12 + 12 = 72 (g / mol);
w (H) = (12/72) * 100 = 18%;
M (C6H6) = 12 * 6 + 6 = 78 (g / mol);
w (H) = (12/78) * 100 = 15%;
Answer: C5H12> C6H6.
b) M (NH3) = 14 + 3 = 17 (g / mol);
w (H) = (3/17) * 100 = 18%
M (H2O2) = 2 + 16 * 2 = 34 (g / mol);
w (H) = (2/34) * 100 = 6%;
Answer: NH3> H2O2.
c) M (CH4) = 12 + 4 = 16 (g / mol);
w (H) = (4/16) * 100 = 25%
M (N2H4) = 14 * 2 + 1 * 4 = 32 (g / mol);
w (H) = (4/32) * 100 = 13%;
Answer: CH4> N2H4.
d) M (C2H4) = 12 * 2 + 4 = 28 (g / mol);
w (H) = (4/28) * 100 = 14%
M (SiH4) = 29 + 1 * 4 = 33 (g / mol);
w (H) = (4/33) * 100 = 12%;
Answer: C2H4> SiH4.