Determine the absolute mass: a) O2 molecules b) C12H22O11 molecules
| December 16, 2020 | education
a) M (O2) = 2 16 = 32 g / mol
m = M / Mr = 32 / 6.02 10 ^ 23≈5.3 10 ^ -23 g
b) M (C12H22O11) = 12 12 + 22 + 11 16 = 342 g / mol
m = M / Mr = 342 / 6.02 10 ^ 23≈56.8 10 ^ -23 g
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