Determine the acceleration of an electron in a uniform electric field of 200 kV / m.

Determine the acceleration of an electron in a uniform electric field of 200 kV / m. the electron charge is 1.6 * 10 ^ -19kl, and its mass is 9.1 * 10 ^ -31kg.

q = 1.6 * 10 ^ -19 Cl.

m = 9.1 * 10 ^ -31 kg.

E = 200 kV / m = 200000 V / m.

but – ?

According to 2 Newton’s law, the acceleration of an electron a is directly proportional to the force F that acts on it, and inversely proportional to its mass m: a = F / m.

Since the electron is a charged particle with a charge q = 1.6 * 10 ^ -19 C, then an electrostatic force F acts on it with an electric field, the value of which is expressed by the formula: F = E * q.

a = E * q / m.

a = 200000 V / m * 1.6 * 10 ^ -19 C / 9.1 * 10 ^ -31 kg = 35165 * 10 ^ 12 m / s2.

Answer: in a uniform magnetic field, the electron will move with acceleration a = 35165 * 10 ^ 12 m / s2.