Determine the acceleration of gravity at the equator if the body falls from a height of 489 m in 10 s.

Problem data: h (height from which an arbitrary body began to free fall) = 489 m; t (duration of fall) = 10 s.

To determine the value of the acceleration of gravity at the equator, we use the formula: S = h = V0 * t + a * t ^ 2/2 = 0 + g * t ^ 2/2, whence g = 2h / t ^ 2.

Let’s perform the calculation: g = 2 * 489/10 ^ 2 = 9.78 m / s2.

Answer: Acceleration of free fall at the equator, according to the calculation, is 9.78 m / s2.