Determine the acceleration of gravity on the surface of Mars, provided that there a mathematical

Determine the acceleration of gravity on the surface of Mars, provided that there a mathematical pendulum with a length of 0.4 m would perform 20 oscillations in 40 s.

Given: l (length of the mathematical pendulum) = 0.4 m); n (the number of oscillations that the pendulum could make) = 20 oscillations; t (oscillation duration) = 40 s.

The free fall acceleration on the surface of Mars is determined from the equality: T = t / n = 2Π * √ (l / g), whence l / g = t ^ 2 / (n ^ 2 * 4Π ^ 2) and g = l * n ^ 2 * 4Π ^ 2 / t ^ 2.

Let’s make the calculation: g = 0.4 * 20 ^ 2 * 4 * 3.14 ^ 2/40 ^ 2 ≈ 3.94 m / s2.

Answer: On the surface of Mars, the acceleration of gravity is 3.94 m / s2.