Determine the acceleration of gravity on the surface of Mercury if its mass is 3.26 * 10 ^ 23 kg, and its radius is 2.42 * 10 ^ 6 meters
Constant data: G (gravitational constant) = 6.67 * 10 ^ -11 m3 / (kg * s2); by condition we take Mm (mass of Mercury) = 3.26 * 10 ^ 23 kg; Rm (radius of Mercury) = 2.42 * 10 ^ 6 m.
Free fall acceleration near the surface of Mercury can be determined by the formula: g = G * Mm / Rm2.
Let’s make the calculation: g = 6.67 * 10 ^ -11 * 3.26 * 10 ^ 23 / (2.42 * 10 ^ 6) ^ 2 = 3.71 m / s2.
Answer: According to the calculation, the acceleration of gravity near the surface of Mercury is 3.71 m / s2.
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