Determine the acceleration of the car if its mass is 2.9 t, the traction force is 650 kN and the coefficient

Determine the acceleration of the car if its mass is 2.9 t, the traction force is 650 kN and the coefficient of friction is 0.007.

Traction force and friction force act on the car, these forces are directly opposite. According to Newton’s second law:
ma = Ft – Ftr, where m is the mass of the car (m = 2.9 t = 2900 kg), a is the acceleration of the car, Ft is the traction force (Ft = 650 kN = 650 * 10 ^ 3 N), Ftr is the friction force (Ffr = µ * N, µ is the coefficient of friction (µ = 0.007), N is the reaction force of the support, N = m * g, g is the acceleration of gravity (g = 10 m / s ^ 2)).
a = (Ft – Ftr) / m = (Ft – µ * m * g) / m = ((650 * 10 ^ 3) – 0.007 * 2900 * 10) / 2900 ≈ 224 m / s ^ 2.
Answer: Vehicle acceleration is 224 m / s ^ 2.