Determine the acute angle of the parallelogram if the height drawn to one of the sides

Determine the acute angle of the parallelogram if the height drawn to one of the sides of the parallelogram is 10 cm and the other side is 10 root of 2 cm.

Since BH is the height of a parallelogram, triangle ABH is rectangular.

An acute angle BAН opposite to the leg BH, then SinВAН = BH / AB = 10/10 * √2 = 1 / √2 = √2 / 2.

Then arcsin (√2 / 2) = 45.

Answer: The acute angle of the parallelogram is 45.



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