Determine the acute angle of the parallelogram if the height drawn to one of the sides of the parallelogram is 10 cm and the other side is 10 root of 2 cm.
Since BH is the height of a parallelogram, triangle ABH is rectangular.
An acute angle BAН opposite to the leg BH, then SinВAН = BH / AB = 10/10 * √2 = 1 / √2 = √2 / 2.
Then arcsin (√2 / 2) = 45.
Answer: The acute angle of the parallelogram is 45.
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