Determine the air pressure in a vessel with a volume of 0.002 m ^ 3, if its mass is 0.012 kg

Determine the air pressure in a vessel with a volume of 0.002 m ^ 3, if its mass is 0.012 kg, temperature is 27c, and its molar mass is 0.029 kg / mol

These tasks: V (volume of air in the vessel) = 0.002 m3; m (air mass) = 0.012 kg; T (absolute air temperature in the vessel) = 27 ºС = 300 K.

Reference values: R (universal gas constant) = 8.31 J / (mol * K); according to the condition M (molar mass of air) = 0.029 kg / mol.

The air pressure in the vessel can be calculated using the Mendeleev-Clapeyron law: P * V = (m / M) * R * T and P = m * R * T / (V * M).

Let’s make the calculation: P = 0.012 * 8.31 * 300 / (0.002 * 0.029) = 515793 Pa ≈ 516 kPa.