Determine the amount of aluminum substance reacted with 150 g of sulfur?

univerkov | January 17, 2021 | education

Given:
m (S) = 150 g
Find: n (Al)
Decision:
2Al + 3S = Al2S3
n (S) = m / M = 150 g / 32 g / mol = 4.7 mol
n (S): n (Al) = 3: 2
n (Al) = 4.7 mol: 3 * 2 = 3.13 mol
Answer: 3.13 mol

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