Determine the amount of calcium carbonate substance, the decomposition of which formed 5.6 g of calcium oxide
| July 20, 2021 | education
The decomposition reaction of calcium carbonate is described by the following chemical equation:
CaCO3 = CaO + CO2;
From 1 molecule of lime, 1 molecule of calcium oxide is synthesized.
Let’s calculate the chemical amount of a substance contained in 5.6 grams of calcium oxide.
M CaO = 40 + 16 = 56 grams / mol;
N CaO = 5.6 / 56 = 0.1 mol;
The same amount of calcium carbonate is required, equal to 0.1 mol.
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