Determine the amount of carbon monoxide (IV) substance formed during the combustion of 56 liters of methane.

The methane combustion reaction is described by the following chemical equation:

CH4 + 3O2 = CO2 + 2H2O;

To burn 1 mole of methane, 3 moles of oxygen are required. This synthesizes 1 mol of carbon dioxide.

Let’s calculate the amount of methane available.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

N CH4 = 56 / 22.40 = 2.5 mol;

The same amount of carbon dioxide will be synthesized.

N CO2 = N CH4 = 2.5 mol;