Determine the amount of chlorine required for complete chlorination of 44.8 liters of methane.
| December 8, 2020 | education
Given: VCH4 = 44.8.
Find: vCl2.
We compose the reaction equation:
CH 4 + 2Cl2 = CCl4 + 2H2
From the reaction equation, we calculate the amount of methane substance taken for the reaction:
nCH4 = v / ∨m = 44.8 / 22.4 = 2 mol, it follows that there is 2 times more chlorine, nCl2 = 2 * 2 = 4 mol
We calculate the amount of chlorine:
∨Cl2 = nCl2 * VCl2 = 4 mol * 22.4 l / mol = 89.6 l.
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