Determine the amount of ethane substance (mol) obtained by the reaction of 13 g of acetylene with 1.4

Determine the amount of ethane substance (mol) obtained by the reaction of 13 g of acetylene with 1.4 mol of hydrogen. reaction equation: C2H2 + 2H2 = C2H6

In accordance with the condition of the problem, we write the equation:
m = 13 g. Y = 1.4 mol Y (mol) -?
1. C2H2 + 2H2 = C2H6 – hydrogenation reaction, ethane was obtained;
1 mol; excess of 1 mol;
2. Let’s calculate the molar mass:
M (C2H2) = 26 g / mol.
3. Determine the number of moles of acetylene, if the mass is known:
Y (C2H2) = m / M = 13/26 = 0.5 mol.
4. Y (C2H6) = 0.5 mol, since the amount of these substances according to the equation is 1 mol.
Answer: the amount of ethane substance is 0.5 mol.