Determine the amount of gas substance that is formed by the interaction of calcium carbonate with hydrochloric

Determine the amount of gas substance that is formed by the interaction of calcium carbonate with hydrochloric acid; the mass of the salt is 115 grams and contains 16% of impurities.

The reaction of interaction of calcium carbonate with nitric acid is described by the following chemical equation:

CaCO3 + 2HNO3 = Ca (N03) 2 + H2O + CO2;

1 carbonate molecule interacts with 2 acid molecules. This synthesizes 1 molecule of carbon dioxide.

Let’s calculate the available chemical amount of pure calcium carbonate.

Its weight is 115 x 0.84 = 96.6 grams;

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 96.6 / 100 = 0.966 mol;

The same amount of carbon dioxide will be synthesized.

1 mole of ideal gas in normal condition takes on a volume of 22.40 liters.

V CO2 = 0.966 x 22.40 = 21.64 liters;