Determine the amount of gas that will be released during the combustion of 500 g of methanol.

The oxidation reaction of methanol is described by the following chemical reaction equation.

CH3OH + 3/2 O2 = CO2 + 2H2O;

According to the coefficients of this equation, 1.5 oxygen molecules are required to oxidize 1 molecule of methanol. This synthesizes 1 molecule of carbon dioxide.

Let’s calculate the amount of methanol available.

To do this, we divide the mass of the substance by its molar weight.

M CH3OH = 12 + 4 + 16 = 32 grams / mol;

N CH3OH = 500/32 = 15.625 mol;

The amount of carbon dioxide will also be 15.625 mol.

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V CO2 = 15.625 x 22.4 = 350 liters;