Determine the amount of heat released during 1 hour in an electric stove, if it is turned on under a voltage of 220 V
| January 3, 2021 | education
Determine the amount of heat released during 1 hour in an electric stove, if it is turned on under a voltage of 220 V, and the resistance of its spiral is 55 Ohm.
According to the Joule-Lenz law, the amount of heat that will be released in an electric stove:
Q = U ^ 2 * t / R, where U is the voltage in the network (U = 220 V), t is the time of passage of the electric current (t = 1 h = 60 * 60 s = 3600 s), R is the resistance of the electric stove spiral (R = 55 ohms).
Let’s calculate the released amount of heat:
Q = U ^ 2 * t / R = 220 ^ 2 * 3600/55 = 3168000 J = 3.168 MJ.
Answer: 3.168 MJ of heat will be released in an electric hotplate.
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