Determine the amount of heat released for every 5 minutes in an electric furnace connected

Determine the amount of heat released for every 5 minutes in an electric furnace connected to a 220V network, if the current in its winding is 2A.

These tasks: t (duration of the furnace) = 5 min (in the SI system t = 300 s); U (mains voltage) = 220 V; I (current in the winding of the furnace in question) = 2 A.

To determine the amount of heat allocated by the furnace under consideration, we use the formula: Q = U * I * t.

Calculation: Q = 220 * 2 * 300 = 132 * 10 ^ 3 J (132 kJ).

Answer: The furnace in question will release 132 kJ of heat in 5 minutes of operation.



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