Determine the amount of heat released in the conductor in 0.5 hour, if the current strength

Determine the amount of heat released in the conductor in 0.5 hour, if the current strength is 0.1A, and the resistance of the conductor is 20 ohms.

Given: t (duration of heat release by the conductor) = 0.5 h (30 min, 1800 s); I (current) = 0.1 A; R (resistance of the taken conductor) = 20 ohms.

The amount of heat released in half an hour on the conductor is determined by the Joule-Lenz law: Q = I ^ 2 * R * t.

Calculation: Q = 0.1 ^ 2 * 20 * 1800 = 360 J.

Answer: 360 J of heat will be released on the conductor in half an hour.



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