Determine the amount of heat required to heat a solution of 300 g of water and 50 g of alcohol to 70 (celsius).

| July 4, 2021 | education

Determine the amount of heat required to heat a solution of 300 g of water and 50 g of alcohol to 70 (celsius). The initial temperature of the solution is 20 (gr. Target). The specific heat capacity of water is 4200 J / (kg * celsius), the specific heat of alcohol is 2500 J / (kg * celsius).

Initial data: m1 (mass of water in solution) = 300 g (0.3 kg); m2 (mass of alcohol in solution) = 50 g (0.05 kg); tк (required solution temperature) = 70 ºС; tн (solution temperature before heating) = 20 ºС.

Constants: according to the condition C1 (specific heat of water) = 4200 J / (kg * ºС); C2 (specific heat of alcohol) = 2500 J / (kg * ºС).

The formula for calculating the required amount of heat will be: Q = (C1 * m2 + C2 * m2) * (tк – tн).

Calculation: Q = (4200 * 0.3 + 2500 * 0.05) * (70 – 20) = 69 250 J.



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