Determine the amount of heat required to melt at normal atmospheric pressure 0.5 kg of lead taken at the melting point.
| April 4, 2021 | education
Given: m (mass of lead) = 0.5 kg; melting of lead occurs at normal atmospheric pressure; the lead before smelting was at the melting temperature (327.4 ºС).
Constants: λ (specific heat of fusion) = 25 * 10 ^ 3 J / kg.
You can determine the required amount of heat for melting 0.5 kg of lead by the formula: Q = λ * m.
Calculation: Q = 25 * 10 ^ 3 * 0.5 = 12.5 * 10 ^ 3 J (12.5 kJ).
Answer: For melting 0.5 kg of lead, 12.5 kJ of heat will be required.
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